Memset 3 F
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There is no fixed way to represent Infinity. The first option that might come to our mind is 0x7f ff ff ff = 2^31 - 1 = 2,147,483,647
which is the maximum value of 32-bit int
.
This choice has one issue -- when adding Infinity with another number, you will get overflow error.
A better choice is 0x3f 3f 3f 3f = 1,061,109,567
.
It is of the same order of magnitude as 0x7f ff ff ff
but twice of it is still within the range of int
.
When using memset
to initialize an array of int
, since memset
is filling values as unsigned char
, memset(A, 0x3f, sizeof(A))
will perfectly fill 0x3f 3f 3f 3f
into the array.